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Krystian Karczyński- 24 June 2024
- Komentarz 0
Harder function limits to calculate often require substitution, for example:
Example
The limit in the numerator does not exist, in the denominator it approaches zero… What does the whole thing approach?
A convenient substitution would be: 
From the substitution, it follows that: 
And that if 
, then 
. So we have:
And this limit does not exist, which can be proven in the manner shown in another of my posts.
