The arctan Formula in Typical Indefinite Integrals
We’ve gotten used to using this formula: 
in „pure” integral situations,
such as:
Then we simply transform…
…and elegantly arrive at the result:
The arctan Formula in Atypical Situations in Indefinite Integrals
And what about this indefinite integral:
? What squared equals 17? Nothing? Nope… 
squared equals 17, so:
Generally speaking, the formula will handle any indefinite integral of this type, constants in the denominator may not be so easy to represent as a square…
