Proving that sinx does not reach a limit as x approaches infinity

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Krystian Karczyński

We have the limit of the function:

We intuitively feel that the above limit does not exist. x’s are getting bigger and bigger, and the sine values ​​are constantly fluctuating between -1 and 1.

Formal proof

But how can we formally demonstrate and prove this?

From the definition of the limit of a function as x approaches infinity , we know that the limit exists if for each sequence of arguments of the function diverging in the corresponding sequence of function values ​​converges to the same number (then this number is the limit).

To show that such a limit does not exist, it is enough to take two random sequences of arguments diverging in and show that the corresponding sequences of values ​​converge to two different numbers.

We know that the sine function is periodic, so these can be, for example, the sequences:

Of course, both sequences diverge to infinity at

Now let’s look at the corresponding sequences of function values : :

Of course, the first sequence converges to 0, and the second sequence converges to 1.

This is enough to prove that the limit of the function:

does not exist.

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