The arctan Formula in Typical Indefinite Integrals
We’ve gotten used to using this formula:
in “pure” integral situations,
such as:

Then we simply transform…

…and elegantly arrive at the result:

The arctan Formula in Atypical Situations in Indefinite Integrals
And what about this indefinite integral:
? What squared equals 17? Nothing? Nope…
squared equals 17, so:
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Generally speaking, the formula
will handle any indefinite integral of this type, constants in the denominator may not be so easy to represent as a square…
